find the value of cos 90°+cos^245°sin 30°+tan^245°sec^230°
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2
Answer:
Given
csc30
∘
+sec60
∘
−cot
2
30
∘
tan
2
60
∘
+4cos
2
45
∘
+3sec
2
30
∘
+5cos
2
90
∘
=
2+2−(
3
)
2
(
3
)
2
+4(
2
1
)
2
+3(
3
2
)
2
+5(0)
=
2+2−3
3+4(
2
1
)+3(
3
4
)
=3+4(
2
1
)+3(
3
4
)
=3+2+4
=9
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