2. A bullet moving with speed 100m/s, gets embedded in the trunk of a tree. It comes to
rest after 5 cm. Find the deceleration offered by the tree. Find the force felt by the bullet if its mass is 100g.
Answers
Correct Question
A bullet moving with speed 100m/s, gets embedded in the trunk of a tree. It comes to rest after 5 sec. Find the deceleration offered by the tree. Find the force felt by the bullet if its mass is 100g.
Solution-
A bullet moving with a speed of 100 m/s (here the initial velocity of the bullet is 100 m/s). The bullet embedded in the trunk of a tree and comes to rest after 5 sec. (Final velocity of the bullet is 0 m/s and time is 5 sec).
We have to find the deceleration offered by the tree.
Using the First Equation Of Motion:
v = u + at
Substitute the known values,
→ 0 = 100 + a(5)
→ -100 = 5a
→ -20 = a
(Negative sign shows retardation)
Therefore, the deceleration offered by the tree is 20 m/s².
Also given that, mass of the bullet is 100 g.
We have to find the force felt by the bullet.
1 g = 0.001 kg
100 g = 0.1 kg
Force is defined as the product of mass and acceleration.
F = ma
Substitute the values,
→ F = 0.1 × (20)
→ F = 2
Therefore, the force felt by the bullet is 2N.
Answer:
Explanation:
Correct Question,
A bullet moving with speed 100m/s, gets embedded in the trunk of a tree. It comes to rest after 5 sec. Find the deceleration offered by the tree. Find the force felt by the bullet if its mass is 100g.
Solution,
Here, we have
Initial velocity, u = 100 m/s
Final velocity, v = 0
Time taken, t = 5 sec
Mass, m = 100 g = 100/1000 = 0.1 kg
To Find,
Deceleration, a = ?
Force, F = ?
Now, According to the 1st equation of motion,
We know that
v = u + at
So, putting all the values, we get
v = u + at
⇒ 0 = 100 + a × 5
⇒ - 100 = 5a
⇒ - 100/5 = a
⇒ a = - 20 m/s²
Hence, the deceleration of the bullet is - 20 m/s².
Now, we will find out Force,
We know that,
F = ma
So, putting all the values, we get
F = ma
⇒ F = 0.1 × 20
⇒ F = 2 Newtons.
Hence, the force felt by the bullet if its mass is 100 g is 2 Newtons.