Question

2) A bullet of mass 0.020 kg is fired; it strikes the wooden block of 0.50kg and sticks in it
The bullet and wooden block move off together with a velocity of 100 m/s. What is the
momentum of the bullet with wooden block?​

Answer 1

Answer:

Let the recoil velocity of gun be V.

Mass of gun Mgun=5.0 kg

Mass of bullet Mbullet=0.01 kg

Velocity of bullet Vbullet=250 m/s

Initial momentum of the system Pi=0

Applying the conservation of linear momentum : Pf=Pi

Or MgunV+MbulletVbullet=0

Or 5×V+0.01×250=0

⟹ V=−0.5 m/s

Explanation:

value change kar lena bro