Question

2) A bullet of mass 0.05 kg is fired from a rifle with a velocity of 800 m/s. After passing through a wall of thickness
1 m; its velocity reduces to 200 m/s. Find the resistive force of the wall.
Ans:- F=-15KN.
(Feb 2016)​

Answer 1

What force is needed and what is the final velocity? ... Find the average specific volume and density of the masses when you exclude air mass and volume. ... Solution: m = mtank + mgasoline = 15 + 0.3 u 800 = 255 kg F = ma = 255 u 6 = 1530 ...... u 0.5 = 0.05m P C.P. T C.P. 2 1 P = 200 kPa 200 T 120 2 1 v v ...

Answer 2

Mass of bullet = 0.05kg
U = 800m/s (initial velocity )
V = 200m/s (final velocity )
S = 1m (distance )

Solution

V^2 - u^2 = 2as
(200)^2 - (800)^2 = 2 x a x s
40000 - 640000 = 2 x a
-600000 = 2a
-300000 = a

F = ma
F = 0.05 x -300000
F = -15000 N
F = -15 KN