Question

2. A bullet of mass 150 g strikes a target
at 600 m/s velocity which is reduced
to 150 m/s. The approximate loss of
energy is :​

Answer 1

Answer:

Loss in Energy = 25312.5

Explanation:

In the question,

Mass of the Bullet, m = 150 g

Initial Velocity of the Bullet, u = 600 m/s

Final Velocity of the Bullet after hitting the target, v = 150 m/s

We know that,

Kinetic energy of the Bullet is given by,

$KE=\frac{1}{2}mv^{2}$

Where, 'm' is he mass of the object

and,

'v' is the velocity of the object.

So,

Change in the Kinetic Energy is the Loss of the Energy which is given by,

$KE_{initial}-KE_{final}=\frac{1}{2}mu^{2}-\frac{1}{2}mv^{2}\\Loss=\frac{1}{2}m(u^{2}-v^{2})\\Loss=\frac{1}{2}\times \frac{150}{1000}(600^{2}-150^{2})\\Loss=0.075(337500)\\Loss=25312.5$

Therefore, the Loss in Energy is given by,

25312.5