Question

2. A car leaves the city at a constant speed of 50 km/h at 6 am, after 1 hour another car also leaves the
city at a constant speed of 60 km/h in the same direction. At what time will both the cars meet​

Answer 1

Answer:

A travelling at 60km/h and due to 1 hour having passed, Car A is 60 kilometers ahead.

Car B travels at 80 km/h

80–60=20 means the car B goes 20 kilometers per hour faster.

Those 20km/h that B catches up to A, Means that out of this 60 kilometer headstart of A, We can calculate:

60/20=3

km/(km/h)= h

So 3 hours to catch up to A…

We know B starts 1 hour later, And A starts at 10 am.

So B starts at 11 am,

11+3=14

Answer 2

Answer:

I THINK ANSWER IS

Step-by-step explanation:

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