Question

2.
A car moving on a straight road accelerates from a speed of 4. 1m/s to a speed of 6.9 m/s in 5.0 s.
Then its average acceleration is
a) 0.1ms-2
b) 0.6 ms2
c) 0.56 ms-2
d) 0.65 ms-2​

Answer 1

Answer :

average acceleration = final speed-initial speed / time taken = 6.9 - 4.1 / 5 = 2.8 / 5 = 0.56 m/s^2

$a_{avg} \: = \frac{ v_{2} - v_{1} }{ t_{2} - t_{1} } \\ \\ = \frac{6.9 - 4.1}{5} = \frac{2.8}{5} \\ \\ = 0.56 {ms}^{2}$

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