Question

2] A conducting wire carries 10^21 electrons in 4 minutes. What is the current flowing through the wire? *

2 points

(a)40A

(b)7A

(c)4A

(d)0.7A

​

Answer 1

Answer:

$\bigstar{\bold{Option\:D:0.7\:A}}$

Explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Number of electrons = 10²¹ electrons
• Time taken (t)= 4 mins = 240 s

$\Large{\underline{\underline{\bf{To\:Find}}}}$

• Current flowing through the conductor (I)

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ First we have to find the charge of the conductor.

→ By quantization of charges we know that

  q = ne

  where e = charge of an electron = 1.6 × 10⁻¹⁹ C

→ Substituting the datas we get,

  q = 10²¹ × 1.6 × 10⁻¹⁹

  q = 1.6 × 10² C

→ The current flowing through a conductor is given by

  I = q/t

→ Substituting the datas we get

  I = 1.6 × 10²/240

  I = 0.67 ≈ 0.7 A

→ Hence current flowing through the conductor is 0.7 A

$\boxed{\bold{Current=0.7\:A}}$

→ Hence option d is correct.

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ Quantization of charge is one of the basic property of charge.

   Electric charge is always an integral multiple of e

   q = ne

Answer 2

Answer:

Given:

Number of electrons = 10²¹ electrons

Time taken (t)= 4 mins = 240 s

\Large{\underline{\underline{\bf{To\:Find}}}}

ToFind

Current flowing through the conductor (I)

\Large{\underline{\underline{\bf{Solution:}}}}

Solution:

→ First we have to find the charge of the conductor.

→ By quantization of charges we know that

q = ne

where e = charge of an electron = 1.6 × 10⁻¹⁹ C

→ Substituting the datas we get,

q = 10²¹ × 1.6 × 10⁻¹⁹

q = 1.6 × 10² C

→ The current flowing through a conductor is given by

I = q/t

→ Substituting the datas we get

I = 1.6 × 10²/240

I = 0.67 ≈ 0.7 A

→ Hence current flowing through the conductor is 0.7 A

\boxed{\bold{Current=0.7\:A}}

Current=0.7A

→ Hence option d is correct.