Question

2. A current of 3.5 ± 0.5 A flows through metallic conductor with a potential difference of 21 ± 1 V is applied. Find the resistance of the wire.​

Answer 1

Given V = 21 + 1 volts

∆V = 1

l = 3.5 + 0.5 A and ∆l = 0.5A

=) Resistance R = V/l

= 21 + 1 / 3.5 + 0.5 = 6 + ∆R

∆R / R = error in measurement =

∆V / V +∆| / |

= 1/21 + 0.5/ 3.5

= 0.048 + 0.143

= 0.191 = 0.19

=} ∆R = 0.19 × R

= 0.19 × 6

=) 1.14

•: Effective resistance R = 6+ 1.14

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