2. A device stores 500 J of energy and releases this energy in the form of an electric
current of 40 A which has a duration of 15 m sec. Determine the average voltage
across the terminals of the devices.
Anyone please answer this question fast
it is urgent
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Answer:
W = VIT
V = W/IT
500/40×15×10^-3
solution: 50×10^2/6
=833.4
Explanation:
W=500j
I=40A
T=15msec=15×10^-3sec
v=?
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