Question

2.
A displacement of a particle starting from rest (at t = 0) is given by x-612-3.
Calculate the time at which the particle will attain zero velocity again. it is not t^3​

Answer 1

Explanation:

Given,

x = 6t^2 - t^3.

velocity = dx/dt

dx/dt = 12t - 3t^2

so particle will attain velocity = 0

=) V = 12t - 3t^2

=) put V = 0

we get ,

=) 3t(4 - t) = 0

we get t = 0 and t = 4 sec

so at t = 0 particle starts and again attains zero velocity at t = 4 sec ..

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Answer 2

Answer:

is this a question of 9th class