find the derivative of 5 sec x + 4 cos x NOT from first principle
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Answer:
let f (x) = 5 sec x + 4 cos x.
now,
f' (x) = (5 sec x + 4 cos x)'
= (5 sec x)' + (4 cos x)'
= 5 (sec x . tan x) + 4 (- sin x)
= 5 sec x . tan x - 4 sin x
let f (x) = 5 sec x + 4 cos x.
now,
f' (x) = (5 sec x + 4 cos x)'
= (5 sec x)' + (4 cos x)'
= 5 (sec x . tan x) + 4 (- sin x)
= 5 sec x . tan x - 4 sin x
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