Chemistry, asked by raj171raj, 10 months ago

The solubility product of a metal carbonate (in which the metal is in +1 oxidation state) is 7.3 x10^-10Calculate its solubility, if the molar mass of the metal carbonate is 250 g/mol.

Answers

Answered by ansh14798234
0

Explanation:

Conversion of Ksp to Solubility

Solubility Product Constants (25°C)

Compound Ksp Compound Ksp

AgBr 5.0 × 10 -13 CuS 8.0 × 10 -37

AgCl 1.8 × 10 -10 Fe(OH) 2 7.9 × 10 -16

Al(OH) 3 3.0 × 10 -34 Mg(OH) 2 7.1 × 10 -12

BaCO 3 5.0 × 10 -9 PbCl 2 1.7 × 10 -5

BaSO 4 1.1 × 10 -10 PbCO 3 7.4 × 10 -14

CaCO 3 4.5 × 10 -9 PbI 2 7.1 × 10 -9

Ca(OH) 2 6.5 × 10 -6 PbSO 4 6.3 × 10 -7

Ca 3 (PO 4 ) 2 1.2 × 10 -26 Zn(OH) 2 3.0 × 10 -16

CaSO 4 2.4 × 10 -5 ZnS 3.0 × 10 -23

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