Question

2. A farmer moves along the
boundary of a square field of side
10 min 40 s. What will be the
magnitude of displacement of the
farmer at the end of 2 minutes 20
seconds from his initial position?
3. Which of the following is true for
displacement?
(a) It cannot be zero.
(b) Its magnitude is greater than
the distance travelled by the​

Answer 1

Answer:

after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.

Explanation:

displacement is zero....

Answer 2

Explanation:(2)

Given side of square =10m, thus perimeter P=40m

Time taken to cover the boundary of 40 m =40 s

Thus in 1 second, the farmer covers a distance of 1 m

Now distance covered by the farmer in 2 min 20 seconds = 1×140=140m

Now the total number of rotation the farmer makes to cover a distance of 140 meters =

perimeter

totaldistance

=3.5

At this point, the farmer is at a point say B from the origin O

Thus the displacement s=

10

2

+10

2

from Pythagoras theorem.

s=10

2

=14.14m

(3)none