2. A farmer moves along the boundary of a square field of side 10 min 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
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Answer:
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Explanation:
Total distance traveled by farmer in 40s=4×10=40m
Total time taken =2min×20sec=140sec
Total number of rounds =
40
140
=3.5
If farmer starts from A, then after 3.5 rounds, he reaches to point
′
C
′
.
Therefore, displacement =AC.
Now, ABCD is a square, then △ABC is a right angled △.
Using Pythagoras theorem,
AC
2
=AB
2
+BC
2
⇒AC=
10
2
+10
2
=
200
=10
2
AC=10×1.414=14.14m
Hence, displacement =14.14m
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