Question

2. A First order reaction is found to have a rate constant K=5.5x10-14 s-1 Find the half life of the reaction.

Answer 1

The half-life of the reaction is 1.26 × $10 ^{13}$ S.

Explanation:

Given,

K = 5.5 * $10^{-14} ^{S-1}$

The formula for finding the half-life of the reaction;

$t_{1/2}$

The association between half-life, K, and the rate constant is;

$t_{1/2}$ = 0.693/k

By putting the value of K,

$t_{1/2}$ = 0.693/(5.5 * $10^{-14} ^{S-1}$)

∵ $t_{1/2}$ = 1.26 × $10 ^{13}$ S

Thus, the half-life of the given reaction is 1.26 × $10 ^{13}$ S.

Learn more: Half-Life of the reaction

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