Question

plzzzzzzzzzzzzzzzzzzzzzzzzz answer the question

Answer 1

GIVEN
4x^2 - 3x + 7
$by \: quadratic \: formula \\ x \: = \: \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ where \: a = 4 \: b = - 3 \: c = 7 \\ x = \frac{3 + - \sqrt{9 - (4 \times 4 \times 7}) }{2 \times 4} \\ x = \frac{3 + - \sqrt{9 - 112} }{8} \\ x = \frac{3 + - \sqrt{ - 103} }{8} \\ as \: the \: discrimnent \: that \: is \: \\ {b}^{2} - 4ac \: is \: - ve \: we \: donot \\ have \: real \: roots \\ therefore \: it \: cannot \: be \: \\ solved$