Question

2. A football is kicked vertically upward from the ground and a student gazing out of the window sees it
moving upwards past her at 5.00 m/s. The window is 15.0 m above the ground. Air resistance may be
ignored. Take g = 10 m/s?.
(a) How high does the football go above ground?
(b) How much time does it take to go from the ground to its highest point?​

Answer 1

Answer:

Explanation:

Let the initial velocity of football is u m/s

Motion from ground to window

v=5m/s

h=15m

v² =u² -2gh

25=u² -2*10*15

u²=325

Motion from window to highest point

u=5 m/s , v=0

v² =u² -2gh

0=25-2*10*h

A)  h=5/4 m

so total height =15+5/4 =65/4 m

motion from ground to max height

u=√325

v=0

v=u-gt

B)  t=√325/10  sec