2)A fraction becoms 1/2 if I is added to the numerator and Denominator and it becomes 1/3 when 1 is subracted from the numerator and 2 is added to Denominator
Answers
GIVEN
fraction becoms 1/2 if I is added to the numerator and Denominator and it becomes 1/3 when 1 is subracted from the numerator and 2 is added to Denominator
TO FIND
Find the required fraction
SOLUTION
Let the required fraction be x/y
**According to the given condition**
★ A fraction becoms 1/2 if 1 is added to the numerator and denominator
→ x + 1/y + 1 = 1/2
→ 2(x + 1) = 1(y + 1)
→ 2x + 2 = y + 1
→ 2x - y = 1 - 2
→ 2x - y = - 1 ---(i)
★ It becomes 1/3 when 1 is subracted from the numerator and 2 is added to Denominator
→ x - 1/y + 2 = 1/3
→ 3(x - 1) = 1(y + 2)
→ 3x - 3 = y + 2
→ 3x - y = 3 + 2
→ 3x - y = 5 ---(ii)
Subtract both the equations
→ (2x - y) - (3x - y) = - 1 - 5
→ 2x - y - 3x + y = -6
→ - x = - 6
→ x = 6
Putting the value of x in equation (i)
→ 2x - y = - 1
→ 2×6 - y = -1
→ 12 - y = -1
→ y = 12 + 1
→ y = 13
Hence,
The required fraction = x/y = 6/13
ɢɪᴠᴇɴ :-
A fraction becoms 1/2 if I is added to the numerator and Denominator and it becomes 1/3 when 1 is subracted from the numerator and 2 is added to Denominator .
ᴛᴏ ғɪɴᴅ :-
- Fraction
Sᴏʟᴜᴛɪᴏɴ :-
➭ Let the fraction be x /y
then,
- ᴀᴄᴄᴏʀᴅɪɴɢ ᴛᴏ 1st ᴄᴏɴᴅɪᴛɪᴏɴs
We get,
➭ 2x - y = -1
➭ y = (2x +1) ---(1)
Now,
- ᴀᴄᴄᴏʀᴅɪɴɢ ᴛᴏ 2nd ᴄᴏɴᴅɪᴛɪᴏɴ :-
We get,
➭ 3x - y = 5. --(2)
Put the value of (1) in (2) , We get,
➭ 3x - (2x + 1) = 5
➭ 3x - 2x - 1 = 5
➭ x = 5 + 1
➭ x = 6
Put x = 6 in (1) , we get,
➭ y = 2x + 1
➭ y = 2×6 + 1
➭ y = 12 + 1
➭ y = 13
Hence,
- Fraction is x/y = 6/13