Question

plzz plzz solve the ques. fasttt

Answer 1

∆ BCD is similar to ∆ CAD.... property of similiarity of right angled triangles.

now,

in both triangles,

AD/CD= CD/BD.....( corresponding sides of similar triangles)

by cross multiplying,

CD×CD= AD×BD

CD^2= AD× BD...... hence proved

hope this helps!! ✌✌☺☺

Answer 2

In ∆ BCA AND ∆ CDA

Angle C = Angle D ------90°

and
Angle A = Angle A ------- common angle

∆ BCA ~ ∆ CDA -------(1)
by A- A test of similarity

Similarly,
∆ BCA ~ ∆ BDC -------(2)

from eq. 1 and 2

∆ CDA ~ ∆BDC
By BPT,

CD/BD = AD/CD

CD² = BD × AD

Hence , proved

Hope it will help you ....