Math, asked by kiran96844, 1 year ago

a man aged 27 marries a woman aged 24 he dies at the age of 81 and she dies at the age of 91 for what fraction of her life is the woman is the widow​

Answers

Answered by CarlynBronk
1

Answer with explanation:

Age of man when he got married =27 years

Dying age of Man =81 years

Difference between marrying age and Dying age of men =81-27=54 years

Age of women,when She got married =24 years

Women's age when her husband died =24 +54 =78 years

Dying age of Women =91 years

Difference of age of women when she got married and when she died =91-24=67 years

Total number of years when women resided alone=91-78=13 years

"The fraction of life when women is widow"that is after her marriage =\frac{13}{67}

otherwise ,The fraction of life when women is widow"that is if women's entire life is of 91 years,then =\frac{13}{91}=\frac{1}{7}

Answered by Anonymous
3

Answer:

hey mate,here is your solution.

hope it will help you.

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