Question

2.
(a) If one root of quadratic equation x2 + 2x - p =0 is.
2, then find the value of p.​

Answer 1

Given:

one root of a quadratic equation $x^{2} +2x-p=0$ is $2$. We have to find the value of $p$.

Since $2$ is a root of the equation.

We have,

$2^{2}+2(2)-p=0$

     $4+4-p=0$

           $8-p=0$

                 $p=8$

We found that the value of $p$ is $8$.

Answer 2

Given:

Quadratic equation: x²+ 2x -p = 0

One of the roots = 2

To find:

The value of p.

Solution:

It was given that one root of the given quadratic equation is 2. If we substitute the value of x with 2, then the equation will become as follows:

2² + 2×2 - p = 0

On simplifying the equation, we will get the following:

4 + 4 - p = 0

On further simplifying, we get the following:

8 - p = 0

On re-arranging, we get:

p = 8

Thus, the value of p will be 2.