Question

2. A juggler keeps on moving four balls in air throwing the balls after regular intervals. When one ball leaves his hand with speed 20 m/s, then it will come again in the hand after time. (g 10 m/s)​

Answer 1

Answer:

My dear friend

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Explanation:

Time taken by the small ball to return to the hands of the juggler is

=2v/g=2×20/10=4s

So, he is throwing the balls after 1s each. Let at some instant, he throws the ball number 4. Before 1s of throwing it, he throws ball 3.