Question

2. A ladder is 13 m long and is placed to reach a window at a height 12 m above the ground. How far from the
wall is the foot of the ladder placed​

Answer 1

Answer:

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Step-by-step explanation:

Length of ladder =13 m.

BC=12m,AC=13 m.

In ΔABC,

AB  

2

+BC  

2

=C  

2

         (Pythagoras theorem)

AB  

2

=AC  

2

−BC  

2

 

=13  

2

−12  

2

 

=169−144

=25

∴AB=5 m.

∴ The distance of the foot of the ladder from the base of the wall =5 m

Answer 2

In this picture :

AC is the ladder, where A is the window, AB is the wall, and BC is to be found :

On using Pythagoras Theorem :

(H)² = (P)²+(B)²

AC² = AB²+BC²

13² = 12²+BC²

13²-12² = BC²

169-144 = BC²

25 = BC²

√25 = BC

BC = 5 m

Distance of ladder from wall = 5 m