Question

2. A man weighing 50 kg lifts a weight of 30 kg to the top of building 10 m high. Find the work
done by him. (take g = 9.8 ms)​

Answer 1

Answer:

solved

Explanation:

the work  done = 80x98 = 7640 j

Answer 2

Hello Mate,

Given:

• Weight of man = 50 kg

• Weight of the object man is lifting = 30kg

• Height of the building = 10 m

• g = 9.8 m/s^2

To Find:

• Total work done by the man

$\huge{\star} {\blue{\underline{\huge{\textsf{Solution}}}}} \huge{\star}$

We know Work Done = mgh

• F = mg,

• s = h

Total weight = 50 + 30 = 80 kg

Substuting values we get,

W = (50 + 30)(9.8)(10)

W = 800 x 9.8

W = 7840 Joules

Hope it helps:)