Question

2. (a) Name the compound CH3COOH and identify its funcational group.
(b) Give a chemical test to identify this compound.
(c) Name the gas evolved when this compound acts on solid sodium carbonate. How would you identify this gas?​
(please answer full , thank you)

Answer 1

Answer:

(a)Acetic acid (CH3COOH)

The functional group present in this compound is a CARBOXYL functional group ( -COOH).

(b) Ethanoic acid reacts with sodium bicarbonate to give CO2 which causes brisk effervescence.

2CH3COOH + Na2CO3 ----------> CH3COONa + H2O + CO2

(c) Acetic acid reacts with sodium bicarbonate as per the reaction given below:-

CH3COOH + NaHCO3 → CH3COONa + H2O + CO2

The gas evolved is carbon dioxide which can be analysed by passing it through lime water, which makes the lime water milky.

Explanation:

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