2) a particle executing S. H. M has an
amplitude of 6cm . It's accelaration at a
distance of 20m from its mean position
is 8 cm/s. The maximum speed of the
Particle is.
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Answer:
a=−ω^2x
ω^2 =4;ω=2 sec/rad
v max =ωA=12^cm
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