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A person is pulling a bucket filled completely with water with the help of a light pulley. Mass of the bucket along with water
contained in it is 20kg. The buoyant force by water is applied to bucket is 5N upwards and viscous force by water also acts
downwards equal to 5N. In this situation the tension in the string is Ti. After some time bucket comes one of water. Now the
tension in string reduces and becomes T2. Accelerations of bucket in water and air are
(ain water
1m/s?, Qin air = 1.5m/s²)
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Answer:
T1=220 N and T2=230N
Explanation:
total force an be given as
F=ma
in water
total force is
due to gravity mg=20×10=200N (g=10m/s^2) downward
tension T1 upward
and buoyant force is 5N upward
viscous force is 5N downward
so
total force is upward force-downward force
so
T1 + 5 - 200 - 5=ma
and
T1=ma+200
and
m= 20kg and a=1m/s^2
so
T1=20×1+200
T1=220N
and in air there will be no viscosity and buoyant force so
total force is
T2 - 200=ma
here m=20 kg and a=1.5m/s^2
so
T2=20×1.5+200
so T2=230N
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