Question

2. A person moves towards East for 3 m, then towards North
for 4 m and then moves vertically up by 5 m. What is his
distance now from the starting point?
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Answer 1

Answer:

what do you mean by this question

Answer 2

The distance from starting point is 5 √2 m.

Explanation:

We are given that:

• Distance covered toward the east (OA) = 3 m
• Distance covered towards the north (AB) = 4 m
• Distance covered in vertical direction (BC) = 5 m
• To Find: Distance from starting point = ?

Solution:

Now by applying Pythagoras theorem = ⊿OAB

Unknown distance (OB) = √OA^2 + AB^2 = √ 3^2 + 4^2

Unknown distance (OB)  = √ 9 + 16 = √25 = 5 m

Now OC = √OB^2 + BC^2 = √5^2 + 5^2 = 5 √2

Thus the distance from starting point is 5 √2 m.