Question

the minimum value of sin 2x-√2 cos2x​

Answer 1

Answer:

1

Step-by-step explanation:

The minimum values of sinx and cosx are possible only when sinx = cosx.

Which is possible only at the value of 45°.

So, sin 2x-√2 cos2x​ = sin90° - √2 cos90° = 1-0 = 1

Hope this helps.....

Answer 2

Answer:

1

Step-by-step explanation:

The minimum value of sinx and coxs are possible only when sinx = coxn which is possible only at the value of 45° so,sin2x -√2 Cox 2x=90° -√2cos 90° =1-0=1

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