Question

2. A person walks along the sides of a square field
Each side is 100 m long. What is the maximum
magnitude of displacement of the person in an
time interval?

Answer 1

Answer:

The maximum ‘magnitude of displacement’ of the ‘person in any time interval’ is 141.42 m.

Given:

A person ‘walks along’ the “sides of a square field” each side is “100m long”.

Then find the maximum ‘magnitude of displacement’ of the person in ‘any time interval’.

Solution:

The maximum displacement is equal to the diagonal of the ‘square field’.

Side of a square, a = 100 m.

Diagonal of the square = $\sqrt{2a}$

=$\sqrt{2*100*100}$

=$100\sqrt{2}$

=$100*1.414=141.42m$

So maximum displacement is 141.42 m.