Question

2. A Point charge 'Q' is placed in an electric field of intensity 'E' The force experienced by the charge will be<br />1.Q/E<br />2.QE<br />3.Q^2E<br />4.E/Q​

Answer 1

Given:

A Point charge 'Q' is placed in an electric field of intensity 'E'.

To find:

Force experienced by the charge?

Calculation:

Force experienced by the charge will be equal to the electrostatic field intensity at that point multiplied by the magnitude of charge.

$\sf \therefore \: F = electrostatic \: intensity \times charge$

$\implies \: \sf \: F = Q \times E$

So, the force experienced is QE. (Option 2)

Additional information:

• If the charge is a positive charge, then the force vector will be directed along $\vec{E}$.

• If the charge is negative, then the force vector will be opposite to the direction of $\vec{E}$.