Question

2. A proton accelerated by
a potential difference V flies
through a uniform
transverse magnetic field
with induction B. The field
occupies a region of space d in thickness. Find
the angle a through which the proton deviates
from the initial direction of its motion.​

Answer 1

Explanation:

sin ¤=d/R

R=mv/qB

sin¤=eBd/mv......(1) [q=e]

E/q=V(V=potential difference)

E=qV

qV=1/2mv^2

v=under root( 2qV/m)

substitute v value in equan 1

sin¤=eBd/m[under root( 2qV/m)]

¤=sin-1(eBd/m[under root( 2qV/m)])