Question

2. A rectangular water tank contains 10.5m^3 water up to a depth of 2m. If the breadth of the tank is 1.75 m, find its length.

Answer 1

Given:-

• Volume of Water tank = 10.5m³

• Height of the tank = 2m

• Breadth of the tank = 1.75m

To Find:-

• Length of tank

Formulae used:-

• Volume of Rectangle = l × b × h

Now,

→ Volume of Tank = l × b × h

→ 10.5 = l × 1.75 × 2

→ 10.5 = l × 3.5

→ 10.5 = 3.5l

→ l = 10.5/3.5

→ l = 3m

Hence, The Length of water tank is 3m

MORE FORMULAE:-

• Volume of Cube = Side × Side × Side

• Volume of Cylinder = πr²h

• Volume of Cone = ⅓πr²h

• Volume of hemisphere = 2/3πr³

• Volume of Sphere = 4/3πr³

Answer 2

Step-by-step explanation:

Given : -

• . A rectangular water tank contains 10.5m³

• water up to a depth of 2m.

• If the breadth of the tank is 1.75 m

To Find : -

• find its length.

Solution : -

$\boxed{ \sf \: Volume \: of \: Tank \: = l \times b \times h}$

Substitute all values :

$\sf : \implies \: 10.5 = l \times 1.75 \times 2 \\ \\ \sf : \implies \:l \: = \frac{ \cancel{10.5}}{ \cancel{1.75 }\times 2} \\ \\ \sf : \implies \: l = \cancel{\frac{6}{2} } \\ \\ \: \sf : \implies \: l = 3$

$\boxed{\begin{minipage}{7 cm}\boxed{\bigstar\:\:\textbf{\textsf{More details}}\:\bigstar}\\\\1) \sf \: Volume of Cube = Side \times Side \times side\\\\2)</p><p> \sf {Volume \: of \: Cylinder} = \pi \: {r}^{2} h\\\\3) \sf {Volume \: of \: Cone } = \frac{1}{3} \pi \: {r}^{2} h \\\\\end{minipage}}$