Question

2.a rocket is fired from indide a deep mine , so as to escape the earth’s gravitational field . the minimum velocity imparted to the rocket is
1.exactly the same as the escape velocity of fire from the earth’s surface.
2. .a little more than the escape velocity of fire from the earth’s surface.
3.a little less than the escape velocity of fire from the earth’s surface.
4.infinity

Answer 1

3.a little less than the escape velocity of fire from the earth's surface

Answer 2

Answer:

The velocity imparted to the rocket is 2. a little more than the escape velocity of fire from the earth’s surface.

Escape velocity:

• The escape velocity is defined as the minimum velocity required for an object to escape the gravitational pull of a primary body.
• After achieving the escape velocity, the object can break from the clutches of gravitational pull and can reach infinite distance.
• The escape velocity is given as $v_e = \sqrt{\frac{2GM}{r}}$, where G is the gravitational constant, M is the mass of the object, and r is the distance between the centers of the object and the body.

Explanation:

Since r is the distance between the centers of the object and the body, the smaller the distance, the greater the escape velocity needed.

• The rocket is fired from inside a deep mine.
• This implies that the distance r is decreased.
• Hence, the escape velocity will be more.

Therefore, to escape the earth's gravitational pull, the rocket should be fired with a little more velocity than the escape velocity.

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