2. A scooter acquire a velocity of 36 km/hr in 19 seconds, just after the start and takes 20 seconds to stop. Calculate the acceleration in both
IT IS PHYSICS NUMERICAL
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bhai maine web ka help le liya im sorry
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Given:
U ( initial velocity) =0 (rest), (final velocity) = 36 km/hr =(1000/3600)
V = 36 ( I don't have multiply sign so am telling u) multiply 5/18 = m/s, t = 10s
From first equation of motion, v = u +at
10 = 0 + a multiply 10
10 = 10 a
a = 10/10
a=1m/s square
Acceleration of scooter =1m/s square
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