Question

2. A square is of area 64 cm². What is its
perimeter?​

Answer 1

Answer:

area of square=s*s

s*s=64

s*s=8*8

s=8

perimeter=4s=4*8=32

Answer 2

AnswEr-:

$\mathrm { Given-:}$

• The area of Square is 64cm².

$\mathrm {To\:Find-:}$

• The perimeter of Square.

$\dag{\mathrm { Solution \:of\:Question-:}}$

$\red{\boxed{\mathrm { Area_{( Square)} = Side \times Side \:or \:Side^{2} \:sq.units}}}$

$\mathrm { Here-:}$

• The Area of Square = 64cm².
• The Side of Square = ??

Therefore,

$\:\:\::\implies { \mathrm { Side^{2} = 64cm^{2} }}$

$\:\:\:\:\::\implies { \mathrm { Side =\sqrt{ 64} }}$

$\:\:\:\:\:\:\::\implies { \mathrm { Side^{2} = 64cm^{2} }}$

$\:\:\:\:\:\:\:\boxed{\pink{ \underline{\mathrm { Side = 8cm }}}}$

Therefore,

• $\dag{\mathrm { \:\:\:Side\:of\:Square-:8cm}}$

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$\red{\boxed{\mathrm {Perimeter _{( Square)} = 4 \times Side \:\:units}}}$

$\mathrm { Here-:}$

• The side of Square = 8 cm

Therefore,

$\:\:\::\implies { \mathrm { 4 \times 8 }}$

$\:\:\:\:\:\boxed{\pink{\underline { \mathrm {Perimeter \:=32 \:cm }}}}$

Hence ,

• $\dag{\mathrm { Perimeter \:of\:Square-:32cm}}$

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$\boxed{\large{\mathrm { |\: More \:to\:know-:\:| }}}$

• $\mathrm {Perimeter _{( Square)} = 4 \times Side \:\:units}$

• $\mathrm { Area_{( Square)} = Side \times Side \:or \:Side^{2} \:sq.units}$

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