Question

2. A stone is released with zero velocity from the top of
a tower, reaches the ground in 4 sec. The height of
the tower is (g-10 m/s)
a) 20m b) 40m c) 80m d) 160 m​

Answer 1

Answer:

80 m

Explanation:

W.K.T

u=0, t=4 s, g=10 m/s

v=u+at

v=0+(10×4)

v=40 m/s

so,to find height

H=v^2/2g

H=(40)^2/2×10

H=1600/20

H=80 m.

Here is ur ans...i hope it helps u

Answer 2

Answer:

80 m is the correct answer