2) A sum of 2400 to be distributed among 6 top
participants of a contest. If each prize amount is 40 less than
its preceding amount, find the highest prize amount
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The highest prize amount = ● 500.
Step-by-step explanation:
Given :
Asum of 2400 which is to be distributed among 6 top participants such that each prize amount is 40 less than its preceding amount.
To find :
The highest prize amount.
Solution :
Since, each amount is 40 less than its preceding
amount, it is a decreasing Arithmetic Progression with common difference 2d = -40
Let the 6 terms of the A.P. be,
a - 5d, a - 3d, a - d, a + d, a + 3d, a + 5d
Adding these 6 terms we get,
6a = 2400 => a = 400.
2d = -40 => d = -20
Therefore, highest prize amount =
a - 5d = 400 - 5 × (-20) = 400 + 100 = 500
Hence, the highest prize amount = ● 500.
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