Question

The equation x2+4+3x=0 hasnumber of real roots with solution

Answer 1

X2+3x+4=0

X2+4x-x+4=0

x(x+4)-1(x+4)

(x+4)(x-1)

x=-4,x=1

Answer 2

Answer:

THE CORRECT ANSWER IS X= - 4 AND 6..

Step-by-step explanation:

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