Question

[2]
A tap supplies water at 10°C and another tap at 100°C. How much hot water must
be taken so that we get 20 kg of water at 35°C ?
[3]​

Answer 1

Given:

Temperature of water from tap 1 = 10°C

temperature of water from tap 2 = 100°C

To find:

How much hot water must be taken to get 20 kg of water at 35°C

Solution:

Since the final temperature will be an average of the product of mass and temperature of water from the two tapes, therefore:

Let the mass of water taken from tap 1 be x.

20 * 35 = x * 10 + (20-x)* 100

700 = 10x + 2000 - 100x

90x = 1300

x = 1300/90 = 14.44 kg

Amount of water taken from tap 2 = 20 - 14.44 kg = 5.56 kg

Therefore amount of hot water required is 5.56 kg.

Answer 2

Answer: 50/9 kg

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