Question

2. (a) The length and the breadth of a rectangle are 16 cm and 12 cm respectively. Find
(i) its perimeter, (ii) the length of its diagonal, and (iii) its area.
​

Answer 1

Step-by-step explanation:

1) perimeter = 2 (l+) =2 (16+12)=56 cm

2) diagonal = underroot l^2 +b^2 =underroot 16^2 +12^2 = underroot 400 = 20cm

3) area= l×b =16×12 = 192 sq.cm

Answer 2

$\Large{\underline{\underline{\green{GiVen:-}}}}$

Length of rectangle = 16 cm

Breadth of rectangle = 12 cm

$\Large{\underline{\underline{\red{To Find:-}}}}$

Diagonal of rectangle

$\Large{\underline{\underline{\green{SoLuTioN:-}}}}$

Let,

ABCD be a rectangle ,

Where ,

AB = CD = 16 cm

BC = DA = 12 cm

Let, BD be a diagonal of rectangle ABCD.

Then, we take a ∆BCD,

According to Pythagoras Theorem ,

BD² = BC² + CD²

BD² = 16² + 12²

BD² = 256 + 144

BD² = 400

BD = √400

BD = 20 cm

Hence

Diagonal of rectangle be = 20 cm

________________