2) a towel when bleached lost 10 % of its length and gained 20% of its breadth ? What is the percentage change in area ?
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New length =L - L/10
new breadth=B + B/5
new area = LB + LB/5 -LB/10 -LB/50
change in area = LB/5 -LB/10-LB/50
CHANGE IN AREA/AREA = 1/5 - 1/10-1/50
=2/25
PERCENTAGE CHANGE =8
new breadth=B + B/5
new area = LB + LB/5 -LB/10 -LB/50
change in area = LB/5 -LB/10-LB/50
CHANGE IN AREA/AREA = 1/5 - 1/10-1/50
=2/25
PERCENTAGE CHANGE =8
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length=x. suppose
breadth=y. suppose
area= xy.
Remaining length...
x- (10x/100)= 9x/10. (1)
breadth after gained...
y+(20y/100)=6y/5. (2)
New area ...
= (9x/10)×(6y/5)
=(27xy)/25
percentage changes in area
(27xy)/25 - xy= 2xy/25
( 2xy/25)×100/(xy)= 8% greater
breadth=y. suppose
area= xy.
Remaining length...
x- (10x/100)= 9x/10. (1)
breadth after gained...
y+(20y/100)=6y/5. (2)
New area ...
= (9x/10)×(6y/5)
=(27xy)/25
percentage changes in area
(27xy)/25 - xy= 2xy/25
( 2xy/25)×100/(xy)= 8% greater
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