Question

a particle is moving in a circle with uniform speed v. in moving from one point to another diametrically opposite point,(where momentum is P=mv) .





1-the magnitude of change in momentum is mv





2-the mangnitude if change in momentum is 2mv





3-the kinetic energy changes by 1/2mv2





4-the kinetic energy changes bymv2



we have to choose from any one option

Answer 1

Answer:

4. the kinetic energy changes by mv2 is the answer.

Answer 2

A particle is moving in a circle with uniform speed v. in moving from one point to another diametrically opposite point the mangnitude if change in momentum is 2mv ( Option 2 is the correct answer)

• The particle's velocity is the same at diametrically opposed places, but in the opposite direction.
• Assume that a particle of mass m is travelling in an anticlockwise direction, and that A and b are diametrically opposed positions.
• Now we have initial momentum of the particle at A is P= mv
• and the final momentum of the particle at B is F= -mv
• Moment um change is = ( F- P) = (- mv- mv) = -2mv
• Also We know the, Initial kinetic energy = ½mv² and Final kinetic energy = ½mv²
• So kinetic energy change = (½mv²-½mv²) = 0
• Momentum changes by 2mv in magnitude but kinetic energy remains same.

Hence, Momentum changes by 2mv in magnitude but kinetic energy remains same.

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