2. a train crosses a pole in 15 seconds while it crosses 100 mtr. Long plat form in 25 sec. The length of the train is
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Hi there!
Here's the answer:
•°•°•°•°<><><<><>><><>°•°•°•°•
Given,
Time taken by train to cross a pole = 15 sec
Length of platform = 100 m
Time taken by train to cross the platform = 25 sec
¶¶¶![Speed\: of \: Train= \frac{Distance\: Covered}{Time\: Taken} Speed\: of \: Train= \frac{Distance\: Covered}{Time\: Taken}](https://tex.z-dn.net/?f=Speed%5C%3A+of+%5C%3A+Train%3D+%5Cfrac%7BDistance%5C%3A+Covered%7D%7BTime%5C%3A+Taken%7D)
Let length of train be ' x ' m
& speed of train be ' y ' m/sec
• Speed of train:
---------(1)
• Speed of train:
---------(2)
Equate (1) & (2)
![\frac{x}{15} = \frac{x+100}{25} \frac{x}{15} = \frac{x+100}{25}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B15%7D+%3D++%5Cfrac%7Bx%2B100%7D%7B25%7D)
=>![25x = 15(x+100) 25x = 15(x+100)](https://tex.z-dn.net/?f=25x+%3D+15%28x%2B100%29)
=>![5x = 3(x+100) 5x = 3(x+100)](https://tex.z-dn.net/?f=5x+%3D+3%28x%2B100%29)
=>![5x = 3x + 300 5x = 3x + 300](https://tex.z-dn.net/?f=5x+%3D+3x+%2B+300)
=>![2x = 300 2x = 300](https://tex.z-dn.net/?f=2x+%3D+300)
=>![x = 150 x = 150](https://tex.z-dn.net/?f=x+%3D+150)
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![\underline{\underline{Length\: of\: train = 150 mts}} \underline{\underline{Length\: of\: train = 150 mts}}](https://tex.z-dn.net/?f=%5Cunderline%7B%5Cunderline%7BLength%5C%3A+of%5C%3A+train+%3D+150+mts%7D%7D)
•°•°•°•°<><><<><>><><>°•°•°•°•
Hope it helps
Here's the answer:
•°•°•°•°<><><<><>><><>°•°•°•°•
Given,
Time taken by train to cross a pole = 15 sec
Length of platform = 100 m
Time taken by train to cross the platform = 25 sec
¶¶¶
Let length of train be ' x ' m
& speed of train be ' y ' m/sec
• Speed of train:
• Speed of train:
Equate (1) & (2)
=>
=>
=>
=>
=>
•°•
•°•°•°•°<><><<><>><><>°•°•°•°•
Hope it helps
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