Question

2. A tree is broken at a height of 5 m from the ground and its top touches the ground at a distance of 12 m from the base of the tree. Find the original height of the tree.

Answer 1

Answer:

Let A'CB be the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, at B. Hence, the total height of the tree(A'B) = A'C + CB = 13 + 5 = 18 m.

Answer 2

Step-by-step explanation:

a tree is broken at =5m

distance of =12m

using Pythagoras theorm

h^2 =p^2+b^2

12^2=5^2+b^2

144=25+b^2

144-25=b^2

119=b^2

√119=b