2(a²+1/a²)-(a-1/a)-7 factorise
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Answer:
(a-1/a+1)(2a-2/a-3)
Step-by-step explanation:
Lets a-1/a=x
x^2 = a^2+1/a^2-2*a*1/a
x^2=a^2+1/a^2-2
therefore a^2+1/a^2 = x^2+2
2(a^2+1/a^2)-(a-1/a)-7
= 2(x^2+2)-x-7
= 2x^2+4-x-7
= 2x^2-x-3
= 2x^2+2x-3x-3
= 2x(x+1)-3(x+1)
=(x+1)(2x-3)
replacing x with a-1/a
(a-1/a+1)(2a-2/a-3)
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