Question

2.
A5g weight is fastened to two helium-filled balloons
with the help of a 1 m long thread. Both the balloons
carry the same charge o and the distance between
them is 0.8 m when the system hangs in equilibrium.
The charge q is
(a) 0.56 uc
(b) luc
(c) 5.6 C
(d1 HC
3
A short electric dipole is placed on a plane. A circle is
on this plane kooning centre of the dinole at
jaaldi btao​

Answer 1

$\huge\green{Answer} -$

Option (a) 0.56 uc is the correct option

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Answer 2

Answer:

Answer:Here B is buoyant force and other symbols are obvious. For vertical equilibrium of the complete system we can write: 2B = mg ⇒ B = mg/2

Answer:Here B is buoyant force and other symbols are obvious. For vertical equilibrium of the complete system we can write: 2B = mg ⇒ B = mg/2=(0.5) (5×10−3) (9.8)

Answer:Here B is buoyant force and other symbols are obvious. For vertical equilibrium of the complete system we can write: 2B = mg ⇒ B = mg/2=(0.5) (5×10−3) (9.8)Now we can write equations for the force diagram of a single balloon.

Answer:Here B is buoyant force and other symbols are obvious. For vertical equilibrium of the complete system we can write: 2B = mg ⇒ B = mg/2=(0.5) (5×10−3) (9.8)Now we can write equations for the force diagram of a single balloon.Vertical equilibrium of balloon: B = T cos θ

Answer:Here B is buoyant force and other symbols are obvious. For vertical equilibrium of the complete system we can write: 2B = mg ⇒ B = mg/2=(0.5) (5×10−3) (9.8)Now we can write equations for the force diagram of a single balloon.Vertical equilibrium of balloon: B = T cos θHorizontal equilibrium of ballorn: T sin θ=Fel

Answer:Here B is buoyant force and other symbols are obvious. For vertical equilibrium of the complete system we can write: 2B = mg ⇒ B = mg/2=(0.5) (5×10−3) (9.8)Now we can write equations for the force diagram of a single balloon.Vertical equilibrium of balloon: B = T cos θHorizontal equilibrium of ballorn: T sin θ=FelHence we have the following equation

Answer:Here B is buoyant force and other symbols are obvious. For vertical equilibrium of the complete system we can write: 2B = mg ⇒ B = mg/2=(0.5) (5×10−3) (9.8)Now we can write equations for the force diagram of a single balloon.Vertical equilibrium of balloon: B = T cos θHorizontal equilibrium of ballorn: T sin θ=FelHence we have the following equationsinθcosθ=FelB ...(i)

Answer:Here B is buoyant force and other symbols are obvious. For vertical equilibrium of the complete system we can write: 2B = mg ⇒ B = mg/2=(0.5) (5×10−3) (9.8)Now we can write equations for the force diagram of a single balloon.Vertical equilibrium of balloon: B = T cos θHorizontal equilibrium of ballorn: T sin θ=FelHence we have the following equationsinθcosθ=FelB ...(i)Fel=14πε0q2(0.6)2