Question

2. Aditya's age is three times his son's age. Ten years ago he was five times his son's age. Find there present ages.​

Answer 1

Answer:

Let Aditya's son age =x

Aditya's age =3x

Ten years ago, he was 5 times the age of his son.

Therefore, 3x−10=5(x−10)

3x−10=5x−50

2x=40

x=20

aditya's son is 20 yrs old

Aditya is 3x=3×20=60 yrs old.

Step-by-step explanation:

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