Question

2. Age of Nandu is 10 years more than that of Anu .Age of Manu is 3 years more than twice
the age of Nandu . The sum of their ages is 53 . Find the their ages ?
(Hint: Take the age of Nandu as x)​

Answer 1

Answer:

Nandu = 10+ Anu            i)

Manu = 3+2 x Nandu

substitute equation i)

Manu = 3 + 2 (10 + Anu)

  Anu + Nandu+ Manu = 53

= Anu + 10 +Anu +3 +  2 (10 + Anu) = 53

Anu + 10 + Anu +3 +  20 + 2 Anu = 53

4Anu =23 = 53

4Anu = 20

Anu = 5 years old

Nandu= 15 years old

Manu = 33 years old

Answer 2

$\sf\underline{\purple{Given:-}}$

Age of nandu is 10 more than that age of anu age

Manu is 3 year more than twice the age of nandu. The sum of their age is 53

$\sf\underline{\purple{To\:Find:-}}$

$Their Ages</p><p>\: \: \:\:\: \: \circ \: \underline{\boxed{\red{\scriptsize{ \sf Hint: take \: the \: age \: of \: nandu \: as \: x}}}} \\ </p><p> </p><p>$

$</p><p></p><p> </p><p>\sf\underline{\purple{Solution:-}}$

Nandu age is 10 years more than Anu

Manu is Twice 3 year more than nandu =

2x + 3

The sum of their age is = 53

4x = 53 + 10 - 3

So 4x = 60

$x =\sf \frac{60}{4} </p><p>$

$[]So \: \: x = 15$

Hence,

• Age of Nandu = 15 years
• Age of Anu = 5 years
• Age of Manu = 33 years

Hope its help u